2(2v^2-4v)+3=0

Solution for 2(2v^2-4v)+3=0 equation:

Simplifying
2(2v2 + -4v) + 3 = 0

Reorder the terms:
2(-4v + 2v2) + 3 = 0
(-4v * 2 + 2v2 * 2) + 3 = 0
(-8v + 4v2) + 3 = 0

Reorder the terms:
3 + -8v + 4v2 = 0

Solving
3 + -8v + 4v2 = 0

Solving for variable 'v'.

Factor a trinomial.
(1 + -2v)(3 + -2v) = 0

Subproblem 1
Set the factor '(1 + -2v)' equal to zero and attempt to solve:

Simplifying
1 + -2v = 0

Solving
1 + -2v = 0

Move all terms containing v to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2v = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2v = 0 + -1
-2v = 0 + -1

Combine like terms: 0 + -1 = -1
-2v = -1

Divide each side by '-2'.
v = 0.5

Simplifying
v = 0.5
Subproblem 2
Set the factor '(3 + -2v)' equal to zero and attempt to solve:

Simplifying
3 + -2v = 0

Solving
3 + -2v = 0

Move all terms containing v to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -2v = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -2v = 0 + -3
-2v = 0 + -3

Combine like terms: 0 + -3 = -3
-2v = -3

Divide each side by '-2'.
v = 1.5

Simplifying
v = 1.5
Solution
v = {0.5, 1.5}